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(A) We use the algebraic identity: $(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx$.Comparing $(x + 2y + 4z)^2$ with the identity,we have $x = x$,$

Vedclass · Accepted Answer

$(x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx)$

Vedclass · Answer

(A) We use the algebraic identity: $(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx$.Comparing $(x + 2y + 4z)^2$ with the identity,we have $x = x$,$y = 2y$,and $z = 4z$.Substituting these values into the identity:$(x + 2y + 4z)^2 = (x)^2 + (2y)^2 + (4z)^2 + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)$.Simplifying each term:$= x^2 + 4y^2 + 16z^2 + 4xy + 16yz + 8zx$.

Expand each of the following,using suitable identities: $(x + 2y + 4z)^2$

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